(t^2+t)/(2)=28

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Solution for (t^2+t)/(2)=28 equation: 


t in (-oo:+oo)

(t^2+t)/2 = 28 // - 28

(t^2+t)/2-28 = 0

(t^2+t)/2+(-28*2)/2 = 0

t^2+t-28*2 = 0

t^2+t-56 = 0

t^2+t-56 = 0

t^2+t-56 = 0

DELTA = 1^2-(-56*1*4)

DELTA = 225

DELTA > 0

t = (225^(1/2)-1)/(1*2) or t = (-225^(1/2)-1)/(1*2)

t = 7 or t = -8

(t+8)*(t-7) = 0

((t+8)*(t-7))/2 = 0

((t+8)*(t-7))/2 = 0 // * 2

(t+8)*(t-7) = 0

( t+8 )

t+8 = 0 // - 8

t = -8

( t-7 )

t-7 = 0 // + 7

t = 7

t in { -8, 7 }

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